What os the distance from the point (x,y)from.the origin?
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Answered by
12
Hi mate !!
The coordinates of origin are :- ( 0 , 0 )
x1 = 0
y1 = 0
Given coordinates :- ( x , y )
x2 = x
y2 = y
Using distance formula :-




The coordinates of origin are :- ( 0 , 0 )
x1 = 0
y1 = 0
Given coordinates :- ( x , y )
x2 = x
y2 = y
Using distance formula :-
abhi569:
:-)
Answered by
3
Points :- (x, y)
Origin :- (0,0)
__________________
By distance formula,
Distance =

Distance =

I hope this will help you
-by ABHAY
Origin :- (0,0)
__________________
By distance formula,
Distance =
Distance =
I hope this will help you
-by ABHAY
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