Question

What percent does phosphorous make up in the compound iron (III) phosphate (Fe(PO4))?

Answer 1

Answer:

Molar mass of FePO4 = 150.816361 g/mol

Convert grams Iron(III) Phosphate to moles or moles Iron(III) Phosphate to grams

Molecular weight calculation:

55.845 + 30.973761 + 15.9994*4

Percent composition by element

Element Symbol Atomic Mass # of Atoms Mass Percent

Iron Fe 55.845 1 37.028%

Oxygen O 15.9994 4 42.434%

Phosphorus P 30.973761 1 20.537%

Explanation:

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