Question

what possible values of resultant resistance are possible by the combining two resistors R1=4 ohm and R2=12ohm.

Answer 1

Case 1

If the combination is in series then,

R.R=4ohm + 12ohm

= 16ohm

Case 2

If the combination is in parallel then,

1/R.R=1/4 + 1/12

=4/12=1/3

R.R=3ohm.

Hope this will help you..........

Answer 2

Answer:

16 ohm and 3 ohm

Explanation:

According to the given question,

R1 = 4 ohm and R2 = 12 ohm

And we are asked to find possible equivalent resistance.

We know, there are only two combination of resistors, i.e, series and parallel combination.

For series combination,

• R = R1+R2

Where R is equivalent resistance of series combination of R1 and R2.

Putting the values we get,

• R = 4+12 = 16 ohm

Again, for parallel combination

• 1/R' = 1/R1 + 1/R2

Where R' is equivalent resistance of parallel combination of R1 and R2.

Putting the values we get,

• 1/R' = 1/4 + 1/12

• R' = 4×12/16

• R' = 12/4

• R' = 3 ohm

Thus the two possible equivalent resistance are 3 ohm and 16 ohm.