Question

what potential difference to make an oil drop of mass 1.8×10^-14 kg having a charge of 3×10^-19 c to remain at rest in between two parallel meatal plates separated by 6 mm
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Answer 1

Step-by-step explanation:

g=10m/s² d=6mm=6×10^-3m

q=mgd/V

3×10^-19=1.8×10^-14×10×6×10^-3/V

V=1.8×10^-14×10×6×10^-3/3×10^-19

V=3.6×10^-16/10^-19

V=3.6×10³