Question

What pressure does a 4000N horse exert on the ground if each foot is 10cm^2?​

Answer 1

Answer:

800Pa

Explanation:

Pressure=Force/Area

Force by first foot=4000N

Area of first foot=10cm^2

therefore,

Pressure by first foot=4000/10=400Pa

Force by second foot=4000N

Area of second foot=10cm^2

therefore,

Pressure by second foot=4000/10=400Pa

hence,

Total pressure=400+400=800Pascal.

Answer 2

Given:

Horse exerts force of 4000 N. Surface area of each foot is 10 cm².

To find:

Total force exerted on ground?

Calculation:

Total surface area = 4 × 10 = 40 cm².

So, pressure on ground is :

$\therefore \: P = \dfrac{F}{area}$

$\implies \: P = \dfrac{4000}{ \bigg( \dfrac{40}{1000} \bigg)}$

$\implies \: P = \dfrac{4000}{ \bigg( \dfrac{4}{100} \bigg)}$

$\implies \: P = \dfrac{4000}{ \bigg( \dfrac{1}{25} \bigg)}$

$\implies \: P = 4000 \times 25$

$\implies \: P = 100000 \: pascal$

$\implies \: P = {10}^{5} \: pascal$

So, pressure on ground is 10⁵ Pascal.