Question

what principal will amount to rs 20790 in 2 years at the simple interest of 5% per annum?​

Answer 1

Step-by-step explanation:

Simple Interest = A ×R ×T /100

A = 20790 RS

R= 5% p.c.p.a

T = 2 years

S.I.= 20790×5×2/100

S.I.=207900/100

S.I.= 2079 RS

Answer 2

${\huge{\underline{\sf {\blue{Answer}}}}}$

$\: \:$

$\boxed{ Principal \:\: = \:\: ₹ 18900 }$

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${\huge{\underline{\sf {\purple{Explanation :}}}}}$

$\: \:$

We know,

$SI \: = \: \frac{P R T}{100}$

$A \: - \: P \: = \frac{P R T }{100}$

$\: \:$

where,

A = Amount

P = Principal

R = Rate of interest

T = Time

SI = Simple Interest

Let, the Principal be 'x'

$\: \: \:$

Given,

Amount = ₹ 20790

Time = 2 years

Rate of interest = 5 % per annum

$\: \:$

$A \: - \: P \: = \frac{P R T}{100}$

➣ $20790 \: - \: P = \frac{P \: \times 5 \: \times 2}{100}$

➣ $20790 \: - \: P \: = \: \frac{p \: \times \: 10}{100}$

➣ $20790 \: - \: P = \: \frac{p}{10}$

Transposing 10

$\: \:$

➣ $(20790 - P) \times 10 = P$

➣ $207900 - 10P = P$

Transposing 10P

$\: \:$

➣ $207900 = P \: + \: 10p$

➣ $11P \: = \: 207900$

Transposing 11

$\: \:$

➣ $P \: = \: \frac{207900}{11}$

➣ P = ₹ 18900