Question

what principal will amount to rs 20800 in 2 years at the simple interest of 2% per annum?​

Answer 1

Answer:

$\huge \bf \: Given$

$\tt \leadsto \: Simple intrest\: (SI) = 20800$

$\tt \leadsto \: time \: (t) = 2 \: years$

$\tt \leadsto \: rate \: (r) = 2\%$

$\huge \bf \: To \: do$

$\tt \leadsto \: find \: principal \: (p)$

$\huge \bf \: solution$

As we know that

$\small \boxed { \bf \: simple \: intrest \: = \frac{principal \times \: time \: \times rate }{100} }$

$\sf \implies \: 20800 = \dfrac{p \times 2 \times 2}{100}$

$\tt \implies \: 20800 = \dfrac{p \times 4}{100}$

$\sf \implies \: 20800 = \dfrac{p \times 1}{25}$

$\sf \implies principal \: = 20800 \div 25$

$\sf \implies \: principal = 832$

Answer 2

GIVEN :

• Simple Interest = 20800
• time (t) = 2 years
• rate (r) = 2 %

TO FIND :

• Principal = ?

FORMULA USED :

$\red {\boxed {\tt Simple \: interest \: = \: \dfrac {principal \times time \times rate}{100}}}$

SOLUTION :

$\tt Simple \: interest \: = \: \dfrac {principal \times time \times rate}{100}$

$\implies \tt 20800 \: = \: \dfrac {p \times 2 \times 2}{100}$

$\implies \tt 20800 \: = \: \dfrac {p \times 4}{100}$

$\implies \tt 20800 \: = \: \dfrac {p \times 1}{25}$

$\implies \tt p \: = \: \dfrac {20800}{25}$

$\large \blue {\boxed {\therefore \tt Principal \: = \: 832}}$