Question

What quantity of heat energy must have been applied to a block of aluminum weighing 42.7 g if the temperature of the block of aluminum increased by 15.2°C?

Answer 1

Answer:

The heat absorbed by the block of aluminium is 11,335.13 kJ.

Explanation:

Mass of block of aluminium= 42.7 g

The specific heat of  ,c = 921.096 J/(gK)

Change in temperature of the block$\Delta T$ =15.2°C = 288.2 K

Heat absorbed by the block of aluminum= Q

$Q=mc\Delta T=42.7 g\times 921.096 J/(gK)\times 288.2K=1.1335\times 10^{7} J=11,335.13 kJ$

The heat absorbed by the block of aluminium is 11,335.13 kJ.