Question

what r the 10 consecutive odd numbers whose sum is 1200​

Answer 1

Given:-

• Sum of 10 consecutive odd numbers = 1200.

To Find:-

• 10 consecutive odd numbers.

Solution:-

Let ten odd numbers be x , x+2 , x+4 , x+6 , x+8 , x+10 , x+12 , x+14 , x+16 , x+18.

According to question,

x + x+2 + x+4 + x+6 + x+8 + x+10 + x+12 + x+14 + x+16 + x+18 = 1200

⇒ 10x + 90 = 1200

⇒ 10x = 1200 - 90

⇒ x = 1110/10

⇒ x = 111

So the 10 consecutive odd numbers whose sum is 1200 are :- 111 , 113 , 115 , 117 , 119 , 121 , 123 , 125 , 127 , 129.

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Answer 2

Solution :-

Let ten odd numbers be x , x+2 , x+4 , x+6 , x+8 , x+10 , x+12 , x+14 , x+16 , x+18.

According to question ,

x + x+2 + x+4 + x+6 + x+8 + x+10 + x+12 + x+14 + x+16 + x+18 = 1200

⇒ 10x + 90 = 1200

⇒ 10x = 1200 - 90

⇒ x = 1110/10

⇒ x = 111

So the 10 consecutive odd numbers whose sum is 1200 are :- 111 , 113 , 115 , 117 , 119 , 121 , 123 , 125 , 127 , 129.