Question

what r the roots of the quadratic equation x square =9 ? algebra std 10​

Answer 1

Answer:

x^2=9

equation:

x^2-9

D=b^2-4ac

=0^2-4*1*-9

=0+36

D=36

x=(-b±√D)/2a

x=(0±√36)/2

x=(0±6)/2

x=(0+6)/2,(0-6)/2

x=6/2,-6/2

x=3,-3

Hence zeros are x=3,-3