.What reactance will be offered i) by an inductor of 0.2 H, (ii) by a capacitance of 10µF, to an ac voltage source of 10V,
100 Hz?
Answers
Answer:
Resonant frequency w
o
=
LC
1
∴ w
o
=
4×27×10
−6
1
⟹ w
o
=96.22Hz
Quality factor Q=
R
Lw
o
∴ Q= 4×96.22/8.4
⟹ Q=45.82
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Answer:
Resonant frequency w o = LC 1
∴ w o = 4×27×10 −6 1
⟹ w o =96.22Hz
Quality factor Q= R Lw o
∴ Q= 4×96.22/8.4
⟹ Q=45.82
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Explanation:
In the RC Network tutorial we saw that when a DC voltage is applied to a capacitor, the capacitor itself draws a charging current from the supply and charges up to a value equal to the applied voltage.
Likewise, when the supply voltage is reduced the charge stored in the capacitor also reduces and the capacitor discharges. But in an AC circuit in which the applied voltage signal is continually changing from a positive to a negative polarity at a rate determined by the frequency of the supply, as in the case of a sine wave voltage, for example, the capacitor is either being charged or discharged on a continuous basis at a rate determined by the supply frequency.
As the capacitor charges or discharges, a current flows through it which is restricted by the internal impedance of the capacitor. This internal impedance is commonly known as Capacitive Reactance and is given the symbol XC in Ohms.
Unlike resistance which has a fixed value, for example, 100Ω, 1kΩ, 10kΩ etc, (this is because resistance obeys Ohms Law), Capacitive Reactance varies with the applied frequency so any variation in supply frequency will have a big effect on the capacitor’s, “capacitive reactance” value.