what's the answer tell me how
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this is how it solve
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{3}^{38} ({3}^{2} + 3 + 1 } \div {3}^{39} ({3}^{2} + 3 - 1) = {3}^{38} \times 13 \div ( {3}^{39} \times 11 = 13 \div (3 \times 11) = 11 \div 33
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