Question

what's the kinetic energy in its half way
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Answer 1

mass = 40kg
h= 5m
g=10m/s^2

P.E. = mgh= 40 × 5 × 10
= 2000 J

When it is allowed to fall, u=0

h= 2.5 m
${v}^{2} = {u}^{2} + 2gh \\ {v}^{2} = 2 \times 10 \times 2.5 = 50m {s}^{ - 1}$
k.e. =
$\frac{1}{2} m {v}^{2} \\ = \frac{1}{2} \times 40 \times 50 \\ = 1000j$
k.e.= 1000J

Answer 2

Its 1000J................