Question

what's the next step.....

Answer 1

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Given ....》》》》AB and AC are two tangents to a circle from an external point P.


To prove.....》》》》∠A + ∠BOC = 180°  



Proof .......》》》》 By the theorem, the tangent at any point of a circle is perpendicular to the radius through the point of contact.

Hence ∠OBA =  ∠OCA = 90° In a quadrilateral. ABOC, ∠A + ∠ACO + ∠COB + ∠OBA = 360° (Sum of the angles of a quadrilateral is 360°)

 ∠A + 90° + ∠COB + 90°  = 360° 

∠A + ∠BOC = 180°.



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