Question

What's the no.of my molecules of 50g of limestone

Answer 1

Answer:

Formula mass of caco3=40+12+3-100amu.. 100g Caco3=1mole.. , 50g of caco3=1÷100×50=0.5 mol.

Answer 2

Limestone chemical formula = CaCO₃

Gram Molecular Mass of Ca = 40 g, C = 12 g, O = 16 g

Molar Mass of Limestone = 40+12+48

= 100 g

Given mass = 50 g

Moles = 50/100

= 0.5

No. of molecules = 0.5*6.022*10²³

= 3.011*10²³

I hope this helps.