Question

what's the resistance here? I'm unable to figure out the head or tail of this question...​

Answer 1

Given :

Six resistors are connected as shown in the figure.

To Find :

Equivalent resistance between A and B.

Solution :

A] Equivalent resistance of series :

• R = R₁ + R₂ + ... + Rₙ

B] Equivalent resistance of parallel :

• 1/R = 1/R₁ + 1/R₂ + ... + 1/Rₙ

Let's solve this problem step by step! :)

In the right part, Three resistors of 20Ω, 10Ω and 20Ω are connected in series.

Therefore their equivalent resistance will be 20 + 10 + 20 = 50Ω

After solving it, Two resistors of 50Ω and 30Ω come in parallel.

Their equivalent resistance will be,

➝ (50 × 30) / (50 + 30)

➝ 1500/80

➝ 18.75 Ω

Finally, Three resistors of 10Ω, 18.75Ω and 10Ω come in series$.$

So final equivalent resistance of the circuit will be

➝ Req = 10 + 18.75 + 10

➝ Req = 38.75 Ω