Question

what's the resistance of a 40 watt energy saver if the voltage applied is 210 volt? ​

Answer 1

Explanation:

p=vi

p=v(v/r)

210=40×40/r

r=1600/210

r=160/21

r=160/21

mark as brilliant

40 thnks

Answer 2

Explanation:

R=

$\frac{210 \times 210}{40}$

$\frac{210 \times 21}{4}$

$\frac{4410}{4}$

$1102.5$