What same number should be added to each one of the numbers 15,23,29,44 to obtain numbers which are in proportion
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Answered by
192
Proportion will look like, a/b = c/d,
let us assume the number which we have to add be x
According to the question,
(15+x)/(23+x) = (29+x)/(44+x),
cross multiply,
(15+x)*(44+x) = (29+x)*(23+x),
simplify them,
660 + 59x + x² = 667 + 52x + x²,
=> 7x = 7
=> x = 1
therefore the number that would be added = 1 !
Hope you understand !
let us assume the number which we have to add be x
According to the question,
(15+x)/(23+x) = (29+x)/(44+x),
cross multiply,
(15+x)*(44+x) = (29+x)*(23+x),
simplify them,
660 + 59x + x² = 667 + 52x + x²,
=> 7x = 7
=> x = 1
therefore the number that would be added = 1 !
Hope you understand !
Answered by
1
Step-by-step explanation:
step by step explanation my answer is 1 .....ok..
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