Question

what shoud be subtracted from 3a²-3b+6 to get 4²-b+29​

Answer 1

Let X be subtracted from 3a^2−6ab−3b^2

Then,

3a^2−6ab−3b^2−1−X=4a^2−7ab−4b^2+1

x=3a^2−6ab−3b^2−1−(4a^2−7ab−4b^2+1)

x=3a^2−6ab−3b^2−1−4a^2+7ab+4b^2−1

x=−a^2+ab+b^2−2

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