Question

what should be added to 1/x to make it equal to x^-2​

Answer 1

$let \: a \: should \: be \: added \\ now \\ \frac{1}{x} + a = {x}^{ - 2} \\ a = \frac{1}{ {x}^{2} } - \frac{1}{x} \\ a = \frac{1 - x}{ {x}^{2} } \\ a = (1 - x)( {x}^{ - 2} )$

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