Question

What should be added to – 4x2 + 3x + 1 to get 2x2 – 9x + 1?​

Answer 1

Solution:

Let P be added.

Then, $-4x^{2}+3x+1+P=2x^{2}-9x+1$

$\Rightarrow P=2x^{2}+4x^{2}-9x-3x+1-1$

$\Rightarrow P=6x^{2}-12x$

Answer:

Thus $(6x^{2}+12)$ has to be added.

Answer 2

Step-by-step explanation:

Let the number P be added.

Then, we will get

-4x^{2}+3x+1+P=2x^{2}-9x+1−4x

2

+3x+1+P=2x

2

−9x+1

~ P=2x^{2}+4x^{2}-9x-3x+1-1⇒P=2x

2

+4x

2

−9x−3x+1−1

| P=6x^{2}-12x⇒P=6x

2

−12x

Answer:

Thus your answer is (6x^2+12)

Therefore, (6x^2+12) needs to be added

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