what should be added to 6/(x+1)(x+2) to obtain 18/x²+x-2
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Answer:
x
2
−3x+2=(x−1)(x−2)
divisiblebybothx=1and2(whichareitszero)
putx=1
1−6+11+8=14
putx=2
2
3
−6(2
2
)+11×2+8
=8−24+22+8
=14
Hence 14 is remainder and IT
must be subtracted
from given polynomial
Step-by-step explanation:
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