Math, asked by Arpit7007, 3 months ago

what should be added to 6m^2 - 2m - 4n^2 to get 7m^2+ 4m +3n^2

plz answer fast​

Answers

Answered by srivastavaabhisek826
0

Step-by-step explanation:

Let the number be x than

6 {m}^{2} - 2m - 4 {n}^{2} + x = 7 {m}^{2}  \\ + 4m  + 3 {n}^{2}   \\ 7 {m}^{2} + 4m + 3 {n}^{2} - (6 {m}^{2} - 2m - 4 {n}^{2}) \\ 7 {m}^{2} + 4m + 3 {n}^{2}  \\  - 6 {m}^{2} + 2m + 4 {n}^{2}   \\  {m}^{2} + 6m + 7 {n}^{2}

Answered by anushreedudhoria
0

Answer:

m² + 6m + 7n²

Step-by-step explanation:

For this we subtract 6m² - 2m - 4n² from 7m² + 4m + 3n² :—

7m² + 4m + 3n²

6m² - 2m - 4n²

(-) (+) (+)

m² + 6m + 7n²

Here you go.

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