Question

what should be added to 8/3 to get 4/7​

Answer 1

Answer:

Answer v(=∩_∩=)ﾌ

x+8/3=4/7

$x + \frac{8}{3} = \frac{4}{7}$

$7x + \frac{8 \times 7}{3} = 4$

$7x + \frac{56}{3} = 4$

$21x + 56 = 12$

$21x + 56 - 12 = 0$

$21x + 44 = 0$

$x = \frac{ - 44}{21}$

Answer 2

Answer:

$let \: the \: number \: be \: x \\ According \: to \: question,</p><p> \\ x + \frac{8}{3} = \frac{4}{7 } \\ x = \frac{4}{7} - \frac{8}{3} \\ x = \frac{12 -56 }{21} \\ x = \frac{ - 44}{21}$

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