What should be added to each term of the ratio 20:11 to make it 3:2?
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Step-by-step explanation:
Given :-
The ratio 20:11
To find :-
What should be added to each term of the ratio 20:11 to make it 3:2?
Solution :-
Given ratio = 20 : 11
Let the number should be added to each term be X
Then the ratio becomes 20+X : 11 +X
According to the given problem
The new ratio = 3:2
=> 20+X : 11+X = 3:2
=> (20+X)/(11+X) = 3/2
On applying cross multiplication then
=> 3(11+X) =2(20+X)
=> 33+3X = 40+2X
=> 3X -2X = 40-33
=> X = 7
Therefore, X = 7
Answer:-
The required number for the given problem is 7
Check:-
The given ratio = 20:11
The required number = 7
On adding 7 to each term in the ratio then
The new ratio = (20+7):(11+7)
=> 27:18
=> 27/18
=> (3×9)/(2×9)
=> 3/2
=> 3:2
Verified the given relations in the given problem.
Used formulae:-
→ a:b can be written as a/b
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