for any two vector A and B prove that a vector into b vector ka whole square is equal to a square B square minus dot product of a vector and b vector ka whole square
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Answer:
Given:
∣
∣
∣
∣
a
+
b
∣
∣
∣
∣
2
=∣
a
∣
2
∣
a
∣
2
+2.
a
.
b
+
∣
∣
∣
∣
b
∣
∣
∣
∣
2
=∣
a
∣
2
2
a
.
b
+
b
.
b
=0
(2
a
+
b
).
b
=0
Therefore, 2
a
+
b
⊥
b
.
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