Question

What should be added to x^2-4xy+5y^2 to get 3x^2+8xy-4y^2?​

Answer 1

$( {x}^{2} - 4xy + 5 {y}^{2} ) + \alpha = (3 {x}^{2} + 8xy - 4{y}^{2} ) \\ \\ (3 {x}^{2} + 8xy - 4{y}^{2} ) - ( {x}^{2} - 4xy + 5 {y}^{2} ) = \alpha \\ \\ 3 {x}^{2} + 8xy - 4{y}^{2} - {x}^{2} + 4xy - 5 {y}^{2} = \alpha \\ \\ 2 {x}^{2} + 12xy - 9 {y}^{2} = \alpha$

#lovelove!

Answer 2

Answer:

2x^2 + 4xy + y^2

Step-by-step explanation:

3x^2 + 8xy - 4y^2 - ( x^2 - 4xy + 5y^2)

=3x^2 + 8xy - 4y^2 - x^2 + 4xy - 5y^2

=2x^2 + 12xy - 9y^2

Here is your answer.

Hope this will help you......