Question

What should be added to x^3-3x^2+6x-15 so that it is completely divisible bu x-3?

Answer 1

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x-3=0

x=3

x³-3x²+6x-15=0

3³-3(3)²+6(3)-15=0

27-27+18-15

=3

3 should be minus from the given polynomial

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Answer 2

Answer:

add up -33 in it

hope it helps

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