Question

What should be added to (x+7)(x- 3) to get the product (x-5)(x-2)?

Answer 1

Answer:

$(x - 5)(x - 2) = (x + 7)(x - 3) \\ {x}^{2} - 2x - 5x + ( - 5)( - 2) = {x}^{2} - 3x + 7x + (7)( - 3) \\ {x}^{2} - 7x + 10 = {x}^{2} + 4x - 21$

NOW TRANSPOSE LHS TO RHS,

$= {x}^{2} - 7x + 10 = {x}^{2} + 4x - 21 \\ = {x}^{2} - {x}^{2} + 10 + 21 - 7x - 4x \\ = 31 - 11x$

So 31-11x should be added to (x+7)(x-3) to get the product of (x-5)(x-2)

Step-by-step explanation:

HOPE IT HELPS YOU OUT.....♤

Answer 2

31 — 11X

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