Math, asked by habeebsk31, 2 months ago

what should be added to x²-2xy+3y² to get -5x²+xy+8y²

Answers

Answered by Krishrkpmlakv

0

Answer:

Step-by-step explanation:

Given,

(x^2 - 2xy + 3y ^2) + (-6x ^2 + xy + 5y ^2)

= x ^2 - 2xy + 3y ^2 - 6x ^2 + xy + 5y ^2

= x ^2 - 6x ^2 - 2xy + xy + 3y ^2 + 5y ^2

= - 5x ^2 - xy +8y ^2

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