Question

What should be added to x2 + xy + y to obtain 2x² + 3xy.​

Answer 1

Answer:

$let \: \: \: the \: \: \: \: number \: \: \: be \: \: \: add \: \: \: be \: \: \: a \\ \\ so \\ ( {x}^{2} + xy + y) + a = 2 {x}^{2} + 3xy \\ \\ a= 2 {x}^{2} + 3xy - ({x}^{2} + xy + y )\\ \\ a = 2 {x}^{2} + 3xy - {x}^{2} - xy - y \\ \\ a = 2 {x}^{2} - {x}^{2} + 3xy - xy - y \\ \\ a = {x}^{2} + 2xy - y$

Answer 2

The expression to be added is given by:

(2x2 + 3xy) - (x2 + xy + y2)

= 2x2 + 3xy - x2 - xy - y2

= 2x2 - x2 + 3xy - xy - y2

= x2 + 2xy - y2