what should be added to x²+xy+y² to obtain 2x²+3xy
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Answer:
X^2+2xy-y^2
x^2+xy+y^2+another equation=2x²+3xy
2x^2+3xy-x^2+xy+y^2=X^2+2xy-y^2
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1
= 2x2 + 3xy – (x2 + xy + y2) = 2x2 + 3xy – x2 – xy – y2 – 2x2 – x2 + 3xy – xy – y2 (re-arranging the terms)
∴ x2 + 2xy – y2 should be added to x2 + xy + y2 to get 2x2 + 3xy
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