Math, asked by kimj13017, 4 months ago

what should be subtracted from 2x²-5y²+7z²to get x²-y²+z²​

Answers

Answered by shrutisil487
3

Answer:

I wish it will help you.

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Answered by KingSrikar
6

Let N be subtracted from 2x² - 5y² + 7z² to get x² - y² + z²

\longrightarrow (2x² - 5y² + 7z²) - N = x² - y² + z²

\longrightarrow (2x² - 5y² + 7z²) - N - (2x² - 5y² + 7z²) = (x² - y² + z²) - (2x² - 5y² + 7z²)

\longrightarrow - N = (x² - y² + z²) - (2x² - 5y² + 7z²)

\longrightarrow - N = x² - y² + z² - 2x² + 5y² - 7z²

\longrightarrow - N = x² - 2x² - y² + 5y² + z² - 7z²

\longrightarrow - N = - x² + 4y² - 6z²

\longrightarrow  N = -(- x² + 4y² - 6z²)

\longrightarrow  N = x² - 4y² + 6z²

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