Question

what should be subtracted from 3/4 and -2/3 to get 1/6?​

Answer 1

$\huge{Answer:}$

Let $x$ be the no. required to be subtracted from $\frac{3}{4}$ so that it becomes $\frac{1}{6}$ & $y$ be the no. required to be subtracted from $\frac{-2}{3}$so that it becomes $\frac{1}{6}$

Acc. to The Question

$\frac{3}{4} - x = \frac{1}{6}$

And

$\frac{ - 2}{3} - y = \frac{1}{6}$

We, have to find $x$ & $y$

So,

$\frac{3}{4} - x = \frac{1}{6}$———Given

$x = \frac{3}{4} - \frac{1}{6}$

$x = \frac{9 - 2}{12}$

$x = \frac{7}{12}$

&

$\frac{ - 2}{3} - y = \frac{1}{6}$———Given

$y = \frac{ - 2}{3} - \frac{1}{6}$

$y = \frac{ - 4 - 1}{6}$

$y = \frac{ - 5}{6}$

So, the no. required to be subtracted from $\frac{3}{4}$ so that it becomes $\frac{1}{6}$is $\frac{7}{12}$

&

the no. required to be subtracted from $\frac{-2}{3}$so that it becomes $\frac{1}{6}$is $\frac{-5}{6}$