what should be subtracted from p2-6p+77 so thta it may exactly be divisible by p-1
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Answered by
0
Answer:
2-77
Step-by-step explanation:
I think it is right.
Answered by
0
Answer:
Since on dividing p
2
- 6p + 7 by p -1 the remainder is 2. Hence if 2 is subtracted from p
2
- 6p + 7 then p
2
- 6p + 7 - 2 i.e., p
2
- 6p + 5 will be exactly divisible by p -1.
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