Question

What should be subtracted from p³-7q²+5p-7 to get q²-2p-6​

Answer 1

Given:

Two equations p³-7q²+5p-7 and q²-2p-6

To Find:

What should be subtracted from p³-7q²+5p-7 to get q²-2p-6

Solution:

Let us assume the equation that should be subtracted be $x$

In order to find what to subtract we will subtract x from the given equation and compare it with the result.

The value of x will be the required equation.

Now,

⇒ (p³-7q²+5p-7) -$x$ = q²-2p-6

⇒$x$ = (p³-7q²+5p-7)-(q²-2p-6)

⇒$x$ = (p³+2p+5p-7q²-q²-7+6)

⇒$x$ = (p³+7p-8q²-1)

Hence, the required equation is (p³+7p-8q²-1)

Answer 2

Answer:

Step-by-step explanation:

Given:

Two equations p³-7q²+5p-7 and q²-2p-6

To Find:

What should be subtracted from p³-7q²+5p-7 to get q²-2p-6

Solution:

Let us assume the equation that should be subtracted be

In order to find what to subtract we will subtract x from the given equation and compare it with the result.

The value of x will be the required equation.

Now,

⇒ (p³-7q²+5p-7) - = q²-2p-6

⇒ = (p³-7q²+5p-7)-(q²-2p-6)

⇒ = (p³+2p+5p-7q²-q²-7+6)

⇒ = (p³+7p-8q²-1)