Question

What should be taken away from (2x²4y²+ 5 xy + 20) to obtain-x²-y²+6xy+20​

Answer 1

Answer:

= (3x2 – 4y2 + 5xy + 20) – (-x2 – y2 + 6xy + 20) = 3x2 – 4y2 + 5xy + 20 + x2 + y2 – 6xy – 20 = 3x2 + x2 – 4y2 + y2 + 5xy – 6xy + 20 – 20 (re – arranging the terms) = 4x2 – 3y – xy ∴ 4x2 + 3y2 – xy should be taken away from 3x2 – 4y2 + 5xy + 20 to obtain -x2 – y2 + 6xy + 20Read more on Sarthaks.com - https://www.sarthaks.com/690609/what-should-be-taken-away-from-4y-2-5xy-20-to-obtain-x-2-y-2-6xy-20?show=690611#a690611

Step-by-step explanation:

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Answer 2

Answer:

= (3x2 – 4y2 + 5xy + 20) – (-x2 – y2 + 6xy + 20) = 3x2 – 4y2 + 5xy + 20 + x2 + y2 – 6xy – 20 = 3x2 + x2 – 4y2 + y2 + 5xy – 6xy + 20 – 20 (re – arranging the terms) = 4x2 – 3y – xy ∴ 4x2 + 3y2 – xy should be taken away from 3x2 – 4y2 + 5xy + 20 to obtain -x2 – y2 + 6xy + 20