Math, asked by erallauma9676521660, 4 months ago

What should be taken away from 3x- 4y + 5xy + 20 to get -x-y+ 6xy + 20.

Answers

Answered by niteshsrivastava715

0

Answer:- Let the number be n

3x-4y+5xy+20+ n= -x-y+6xy+20

n= -x-y+6xy+20-(3x-4y+5xy+20)

n=-x-y+6xy+20-3x+4y-5xy-20

n= -4x+3y+xy

Answered by prachiparija2007

0

Answer:

I think the answer is x-y-xy

Step-by-step explanation:

(3x-4y+5xy+20-x)-(3y+6xy+20+x)

=3x-4y+5xy+20-x+3y-6xy-20-x

=3x-2x-4y+3y+5xy-6xy (NOTE=+20 and - 20 gets cancelled)

=x-y-xy (ans)

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