Question

what should be taken away from 5x square +4y square + 10xy to obtain 2x square + 6y square + 9xy pls answer it fast it's urgent ​

Answer 1

$\huge{\boxed{\mathcal{SOLUTION}}}$

Let,

Let,The number be 'a' which must be taken away.

As per the question,

${5x}^{2} + {4x}^{2} + 10xy - a = {2x}^{2} + {6y}^{2} + 9xy$

Now, we have to bring the common variables on the same side for calculation.

It is important to note that when we bring any variable from its actual side to opposite side, there is a conversion of sign i.e., plus turns into minus and minus turns into plus.

${5x}^{2} - {2x}^{2} + {4y}^{2} + 10xy - 9xy = a$

${3x}^{2} - {2y}^{2} + xy = a$

Hence,

Hence, The value which must've taken away from the above mentioned value is

$a = {3x}^{2} - {2y}^{2} + xy$

Answer 2

Your answer is a=<3x^2-2y^2+xy