Math, asked by s137411136, 2 days ago

What should be taken away from 5x2–4y2+20 to obtain x2–3y2+10 ?​

Answers

Answered by vandanathakur822
1

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Answer:

Let us assume the missing part as X.

Therefore according to the question,

(3x2 - 4y2 + 5xy + 20) - (X) = - x2 - y2 + 6xy + 20

Let us shift the terms to find the value of X

X = 3x2 - 4y2 + 5xy + 20 - (- x2 - y2 + 6xy + 20)

X = 3x2 - 4y2 + 5xy + 20 + x2 + y2 - 6xy - 20

X = 4x2 - 3y2 - xy

Thus, the expression that should be subtracted is 4x2 - 3y2 - xy

Answered by krishpmlak
0

Answer:

Step-by-step explanation:

4x² + y² - 10 should be taken away from 5x²- 4y² + 20 to obtain x²- 3y² + 10 .

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