Math, asked by shivangjaiswal188, 3 months ago

what should be taken away from x²-4y²+5xy+50 to obtain -x²-y²+6xy+20

Answers

Answered by mishradeepanshi49

1

Answer:

Step-by-step explanation:

3x2-4y2+5xy+20-(-x2-y2+6xy+20)

=3x2-4y2+5xy+20+x2+y2-6xy-20

=4x2-3y2-xy+0

=4x2-3y2-xy

since the answer was 4x2-3y2-xy

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