Question

What should be the boiling point of 1.0 molal aqueous KCl solution (assuming complete dissociation of KCI)
If K (H2O) is 0.52 km-1?
(1) 101.04°C
(2) 98.5°C
(3) 102.5°C
(4) 105.2°C​

Answer 1

Answer:

Mathematical Expression -

∆Tb=i*Kb*m

wherein i for KCl =2

Kb =elevation constant in boiling point

m=molality

∆Tb=2*0.52*1 = 1.04

Tb =∆Tb+Tb°

Tb =1.04 + 100= 101.04°c