What should be the degree of hydrolysis of 0.01m ammonium acetate solution at 25 °c, if kh = 3.175 × 10–5 :-?
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DEGREE OF HYDROLYSIS - This is the fraction or the percentage salt hydrolyzed at equilibrium.
DEGREE OF HYDROLYSIS = Number of moles hydrolyzed / total number of moles taken.
It is also equal to :
H = √{Kh / C} Where :
Kh = Hydrolysis constant
C = Molarity
Substituting in the formulae :
√{3.175 × 10⁻⁵ / 0.01}
√0.003175 = 0.0563471
The degree of hydrolysis is thus : 0.0563471 to six significant figures
DEGREE OF HYDROLYSIS = Number of moles hydrolyzed / total number of moles taken.
It is also equal to :
H = √{Kh / C} Where :
Kh = Hydrolysis constant
C = Molarity
Substituting in the formulae :
√{3.175 × 10⁻⁵ / 0.01}
√0.003175 = 0.0563471
The degree of hydrolysis is thus : 0.0563471 to six significant figures
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