Question

What should be the depth of an underground water tank holding 3000liters of water having length 2m and breadth 1m.

Answer 1

Answer:

we know that 1m cube is 1000 litres

so 3000 litres means 3 m cube

so ans shd be 2*1*x = 3

depth shd be 1.5 m

Answer 2

Answer:

Question :

What should be the depth of an underground water tank holding 3000liters of water having length 2m and breadth 1m.

$\begin{gathered}\end{gathered}$

Given :

• => Lenght of underground tank = 2m
• => Breadth of underground tank = 1m
• => Volume of underground water tank = 3000 litre

$\begin{gathered}\end{gathered}$

To Find :

• => Depth of underground tank

$\begin{gathered}\end{gathered}$

Using Formula :

${\longrightarrow{\small{\underline{\boxed{\sf{V = l \times b \times h}}}}}}$

• => V = Volume of underground tank
• => l = length of underground tank
• => b = breadth of underground tank
• => h = (height/depth) of underground tank

$\begin{gathered}\end{gathered}$

Solution :

Here,

• => Volume = 3000 litre
• => Length = 2 m
• => Breadth = 1 m
• => Height/depth = ?

So,

Converting the volume of underground water tank into m³. As we know that 1 litre = 0.001 m³.

• => 3000 litre
• => 3000 × 000.1
• => 3 m³

Now, according to the question,

$\dashrightarrow \: \: {\sf{V = l \times b \times h}}$

$\dashrightarrow \: \: {\sf{3 = 2 \times 1 \times h}}$

$\dashrightarrow \: \: {\sf{3 = 2 \times h}}$

$\dashrightarrow \: \: {\sf{3 = 2h}}$

$\dashrightarrow \: \: {\sf{h = 3 \div 2}}$

$\dashrightarrow \: \: {\sf{h = \dfrac{3}{2}}}$

$\dashrightarrow \: \: {\sf{h = \cancel{\dfrac{3}{2}}}}$

$\dashrightarrow \: \: {\sf{h = 1.5 \: m}}$

Hence, the depth of underground tank is 1.5 m.

$\begin{gathered}\end{gathered}$

Verification :

$\dashrightarrow \: \: {\sf{V = l \times b \times h}}$

$\dashrightarrow \: \: {\sf{3 = 2\times 1 \times 1.5}}$

$\dashrightarrow \: \: {\sf{3 =2\times 1.5}}$

$\dashrightarrow \: \: {\sf{3 \: {m}^{3} =3 \: {m}^{3}}}$

$\dashrightarrow \: \: {\sf{LHS=RHS}}$

Hence Verified!

$\begin{gathered}\end{gathered}$

Learn More :

$\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}$

$\rule{220pt}{3pt}$