Question

what should be the differntiation of x√x​

Answer 1

Step-by-step explanation:

$\frac{d}{dx} x \sqrt{x} \\ = > \frac{d}{dx} {x}^{1 + \frac{1}{2} } \\ = > \frac{d}{dx} {x}^{ \frac{3}{2} } \\ = > \frac{3}{2} {x}^{ \frac{3}{2 } - 1 } \\ = > \frac{3}{2} {x}^{ \frac{1}{2} }$

Formula :

$\frac{d}{dx} {x}^{n} = n {x}^{n - 1}$

hope this helps you