Question

what should be the distance between two alfa particle and a proton in air , so that there is a repulsive force of 6×10 power -11 n between them. ​

Answer 1

we know here F = (q1 ×q2)/r^2

one alpha particle has mass 4amu

then it has a charge of 2 (6 ×10^-19)C

now here alpha particle is 2

total charge = 4 (6×10^-19)

6×10^-11 = (4×6 ×10^-19 ×6×10-19)/r^2

6×10^-11 = (144 × 10 ^-38)r^2

r^2 = ( 24× 10^-27 )

r = root 2.4 × 10^-28

Answer 2

Answer:

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