Physics, asked by jayanichona, 7 months ago

what should be the duration of day so that weifht of tge object at equator is 40% of the actual weight?

Answers

Answered by Thakshayini

1

Answer:

Hi there!!

Explanation:

Happy helping...

g app = g -w²r

w= 2 pi /T

where w is omega, angular spped of earth.

T is time period in second in one day.

take g = 10m/s²

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