what should be the least value of x so that the no 6342x1 is divisible by 3?
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Answer:
X=2
Step-by-step explanation:
An no is divisible by 3 if the sum of all its digits is divisible by 3
So, 6+3+4+2+x+1=16+x
No. Nearest to 16 which is divisible by 3 is 18
Therefore, 16 +x=18
=> x=2
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