What should be the power of an engine in the month of November, required to lift 90000 kg of coal per hour from a mine whose depth is 200 m if it works for 6 hour a day ?
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Explanation:
Given, mass of the coal, m=90metrictonnes=90×1000kg=9×10
4
kg ;
height through which the coal is to be lifited;
h=200m;time,t=1h=60×60s=3600s
Work done, W=mgh
=(9×10
4
)(10)(200)=18×10
7
J
Power, P=
t
W
=
3600
18×10
7
=50000W
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