Question

what should be the power of an engine required to lift 90 metric tonnes of coal per hour from a mine whose depth is 200m ?​

Answer 1

Check this attachment....

Answer 2

$\huge\bigstar\mathfrak\purple{\underline{\underline{SOLUTION:}}}$

The work done would be =mgh

90000× 10× 200= 18× 10^7

$</strong><strong>P</strong><strong>ower = \frac{work \: done}{time} \\ \\ = > \frac{18 \times 10 {}^{7} }{3600} \\ \\ = > 0.005 \times {10}^{7} units$

Krishna❤️